《20以內(nèi)退位減法》
20以內(nèi)退位減法1 .在。里填上“>"、或“3011-94015- 92 .做減法,把得數(shù)填在方格內(nèi).3.填空.9+() =13159+() =174.填空.9+() =119+()9+() =149+()120 1 2 3 4 5 6 7 8 9 10 11 12 1314 1500口=口5.看圖列式計算.口???= 口參考答案1,略2. 4 , 6, 8, 103. 9+ (4) =139+ (2) =119+ (6) = 159+ (8) = 179+ (5) = 149+ (3) = 124. 12-9 = 35. 14-9 = 53+ ()=12 -3=()12得多少?1 .判斷題.(1) 167=9 148=72.填空.5+( ) =1414 5=()3 .填空.分別減去8,()()4 + ( ) =1212 -4=()4.在()里填上正確的數(shù),看一看有什么規(guī)律.13 9=3+ ()15 9=5+ ()12 9=2+ ()17 9=7+ ()16 9=6+ ()11 8=1+ ()15- 8 = 5+ ()148 = 4+ ()138 = 3+ ()178 = 7+ ()5.應(yīng)用題.G >Lu Z3_ ,一_ i,、停一費給J)口 = 參考答案93, 6118=1+ (2)15 8=5+ (2)14 8=4+ (2)13 8=3+ (2)17 8=7+ (2)1. (1) V X2. 9, 8 , 9 , 9 , 8 ,3. 4, 8 , 7 , 5 , 9 ,4. 13 9 = 3+ (1)15 9=5+ (1)12 9=2+ (1)17 9=7+ (1)16 9=6+ (1)5. 12 -8= 41 .填空.2 .在。里填運算符號,在口里填數(shù)字.900= 131200= 5700= 1411OD= 11600= 133 .應(yīng)用題.(1)小明要做14朵小紅花.做好了 7朵,還要做幾朵?算式: (朵)答:還要做口朵.(2)商店有熊貓玩具11只,賣掉7只,現(xiàn)在有多少只? = (只)口答:現(xiàn)在有 只.4 .列式計算.16 ()? 參考答案1. 4, 6, 92. 9+4=13, 12-7=5, 7 + 7=14, 110=11, 6+7=133. (1) 14-7=7, 7(2) 11-7 = 4, 44. 16 75=45 + 4+7=16